Calculate voltage drop and check BS 7671 compliance for electrical installations
Check if your cable installation meets BS 7671 voltage drop requirements
Voltage drop calculation is essential for ensuring electrical installations comply with BS 7671 regulations. This guide explains the complete process for UK electrical systems.
BS 7671 Regulation 525 specifies maximum voltage drop limits:
To calculate voltage drop, you need:
The formula differs between single-phase and three-phase systems:
Single-Phase Formula:
For 230V single-phase circuits (most domestic installations)
Three-Phase Formula:
For 400V three-phase circuits (commercial/industrial)
Then convert to percentage: (Voltage Drop ÷ Nominal Voltage) × 100
The millivolt drop per amp per meter (mV/A/m) is found in BS 7671 tables:
These values account for both conductor resistance and reactance at operating temperature.
Given: 32A shower, 15m cable run, 6mm² twin & earth, 230V
Step 1: From Table 4D5, 6mm² cable = 7.3 mV/A/m
Step 2: Calculate voltage drop:
Vd = (7.3 × 15 × 32) ÷ 1000 = 3.504V
Step 3: Convert to percentage:
(3.504 ÷ 230) × 100 = 1.52%
✓ Result: 1.52% is under the 5% limit - compliant with BS 7671
Quick reference voltage drop values (mV/A/m) from BS 7671 for common UK cable types. These values are used in voltage drop calculations.
| Cable Size | mV/A/m | Example: 10m @ 20A | Max Length @ 5% |
|---|---|---|---|
| 1.0mm² | 44 mV/A/m | 8.8V (3.8%) | 26m @ 20A |
| 1.5mm² | 29 mV/A/m | 5.8V (2.5%) | 40m @ 20A |
| 2.5mm² | 18 mV/A/m | 3.6V (1.6%) | 64m @ 20A |
| 4.0mm² | 11 mV/A/m | 2.2V (1.0%) | 52m @ 32A |
| 6.0mm² | 7.3 mV/A/m | 1.46V (0.6%) | 79m @ 32A |
| 10.0mm² | 4.4 mV/A/m | 0.88V (0.4%) | 87m @ 40A |
Reference: BS 7671 Table 4D5 (2-core cables with protective conductor, 70°C thermoplastic)
| Cable Size | mV/A/m (2-core) | mV/A/m (3-core) | Typical Use |
|---|---|---|---|
| 2.5mm² | 18 mV/A/m | 18 mV/A/m | Garden lighting |
| 4.0mm² | 11 mV/A/m | 11 mV/A/m | Garage sub-mains |
| 6.0mm² | 7.3 mV/A/m | 7.3 mV/A/m | EV chargers, outbuildings |
| 10.0mm² | 4.4 mV/A/m | 4.4 mV/A/m | Large outbuildings |
| 16.0mm² | 2.8 mV/A/m | 2.8 mV/A/m | Commercial sub-mains |
Reference: BS 7671 Table 4D4A (Armoured 70°C thermoplastic cables)
💡 Quick Tip: Lower mV/A/m values mean less voltage drop. For long cable runs, use larger cable sizes to reduce voltage drop and stay within BS 7671 limits.
Follow these worked examples to understand voltage drop calculations for common UK installations.
Scenario:
Calculation:
mV/A/m for 2.5mm² = 18 mV/A/m (Table 4D5)
Vd = (18 × 28 × 20) ÷ 1000 = 10.08V
Percentage = (10.08 ÷ 230) × 100 = 4.38%
✓ Result: 4.38% - Within 5% limit for power circuits
Scenario:
Calculation:
mV/A/m for 1.5mm² = 29 mV/A/m (Table 4D5)
Vd = (29 × 35 × 5) ÷ 1000 = 5.075V
Percentage = (5.075 ÷ 230) × 100 = 2.21%
✓ Result: 2.21% - Within 3% limit for lighting
Scenario:
Initial Calculation (6mm²):
mV/A/m for 6mm² SWA = 7.3 mV/A/m (Table 4D4A)
Vd = (7.3 × 40 × 32) ÷ 1000 = 9.344V
Percentage = (9.344 ÷ 230) × 100 = 4.06%
Upgrade to 10mm²:
mV/A/m for 10mm² SWA = 4.4 mV/A/m
Vd = (4.4 × 40 × 32) ÷ 1000 = 5.632V
Percentage = (5.632 ÷ 230) × 100 = 2.45%
✓ Solution: Upgrade to 10mm² SWA for 2.45% voltage drop
Note: 6mm² would work for runs under 28m at 32A
Use this calculator to verify that your cable installation meets BS 7671 voltage drop requirements before energizing the circuit.
Voltage drop is the reduction in voltage that occurs as electrical current flows through a conductor due to the conductor's resistance. Excessive voltage drop can cause:
This calculator checks compliance with BS 7671:2018+A2:2022 Regulation 525 - Voltage drop in consumers' installations.
Under normal service conditions, the voltage drop between the origin of the installation (usually the supply terminals of the consumer unit) and any socket outlet or other point of utilization shall not exceed the values given in Appendix 12:
The calculator uses the following formula:
Where: I = Current (A), L = Length (m), R = Resistance (Ω/m)
Note: Voltage drop is only one consideration. Cable selection must also account for current-carrying capacity, overcurrent protection, and fault protection requirements.